How do I prevent my counter from counting twice?-CodePudding

def counter(user_inp):
    for i in user_inp:
        
        print(f"{i} occurs {user_inp.count(i)} times")
counter([1, 2 ,3, 1])

whenever there is a duplicate number the iterator will print it out again instead of just once. Unsure how to specify that

CodePudding user response：

You need to make your for-loop ignore duplicates - often the easiest way to do this is to convert the list to a set first.

#input is a list of integers
def counter(user_inp):
    for i in set(user_inp):
        print (f"{i} occurs {user_inp.count(i)} times")

CodePudding user response：

If I understood correctly this should solve it for you:

lista = [3, 3, 3, 5, 5, 1, 2, 4]

def counter(x):
    temp = []
    for i in x:
        if i not in temp:
            temp.append(i)
            print(str(i) " occurs " str(x.count(i))  " times")

counter(lista)