c# two parameters in one parameter in a method-CodePudding

I would like to make one method like this:

public void SomeMethod(int myInt,<float or double or MyClass> myFloatorDoubleorMyClass)
{

}

And not only with generics, but also with any class. I would like to avoid this:

public void SomeMethod(int myInt, float myFloat)
{

}

public void SomeMethod(int myInt, double myFloat)
{

}

public void SomeMethod(int myInt, MyClass myClass)
{

}

Is this feasible?

CodePudding user response：

You can use overloading like this:

public void SomeMethod(int myInt, double myDouble)
{
   // ...
}

public void SomeMethod(int myInt, float myFloat)
{
   SomeMethod(myInt, (double)myFloat);
}

Note that this is valid because a float can be put into a double without loosing precision.

Update: The question was updated, and specifically requests to avoid overloading. In this case my answer above is no longer relevant. I still believe (as others who commented on this post) that overloading in this case is prefered over the alternative (using generics).

BTW - In this specific case a float can be automatically converted to a double. But using overloading is a good solution also when you have types that do not convert automatically.

CodePudding user response：

You can achive this with Generics

Could look like

public void SomeMethod<T>(int myInt, T myFloatorDouble)
{

}

But it could be cleaner with overloads like

public void SomeMethod(int myInt, float myFloat)
{

}

public void SomeMethod(int myInt, double myDouble)
{

}

Depends on the logic in your method. If you have to cast inside the method, I would recommend overloads for example.