The output value is 100000 to 10 random natural numbers What should I do to print out only from the right end to the third? And if you print it out with multiple of ten, an error appears so, if we get a multiple of 10, i want to put out 010 something

for example, input -> 6545 output -> 545, input -> 27 output -> 027

and i'm using java. pls help me

CodePudding user response：

Assuming your inputs are actually ints:

System.out.printf("d",inputvalue00); 

should give the result you want:

• "d" forces output with zero padding
• inputvalue00 calculates the remainder of division by 1000 (modulo), which will chop off all digits to the left of the three last

CodePudding user response：

You can transform an Int to a String with String.valueOf(i). Then, you only have to take the 3 last characters of the string and adding 0. Because your "027" is a String, it isn't an Int

CodePudding user response：

    public static void main(String... args) {
  
    Random rand = new Random();
    int upperbound = 100000;
    int lowerbound = 10;
    int random_integer = rand.nextInt(upperbound - lowerbound)   lowerbound;

    String output = String.valueOf(random_integer);
    String finaloutput = output;
    if (output.length() <= 3) {

        for (int i = 0; i < 3 - output.length(); i  ) {
            finaloutput = "0"   finaloutput;
        }
    } else {
        finaloutput = output.substring(0, 3);
    }

    System.out.println(random_integer   "->"   finaloutput);

}