How to extract integer from string with no spaces in between in python?-CodePudding

I want to extract an integer value from string with no spaces between string and integer. The input is in the form 'n12' , 'n46' etc and the output should be like 12 and 46 respectively.

CodePudding user response：

Write loop that takes only digits from string, and then convert it to integer.

def convert_str(ns):
    result = 0
    for c in ns:
        if c.isdigit():
            result *= 10
            result  = int(c)
    return result

CodePudding user response：

You could do something like this, though I am not sure if it is ideal or not

nums = ['0','1','2','3','4','5','6','7','8','9']

s = 'n42'

r = [i for i in s if i in nums] 

r = int(''.join(r))

print(r)

CodePudding user response：

You can just used .replace:

x = 'n12'
x = int(x.replace('n',''))
x

And yes if you have a list you can used a loop with this fonction.

CodePudding user response：

Using regex module you can achieve this

import re
input_str = "n12 n46" # you can use 'n12' as well
temp = re.findall(r'\d ', input_str)
res = list(map(int, temp))
print("The numbers list is : "   str(res))

# Output : The numbers list is : [12, 46]

CodePudding user response：

This is trivial with re.sub.

import re

s = 'n46'

modified = re.sub(r'[^\d]', '', s)

We're substituting anything that isn't ([^ ]) a digit (\d) with nothing.