Is it possible, somehow, to sort array with some "between" numbers?

[31, 33/34, 34, 29].sort((a, b) => a.toString().localeCompare(b.toString()))

//to return [29, 31, 33/34, 34] instead [0.9705882352, 29, 31, 34]

CodePudding user response：

As mentioned in the comments, the only way this will work is if you use string to capture the numbers. The engine is going to store your 33/34 as the decimal. There is no way to get the original value back.

Doing it is just a simple parse and sort.

var nums = ['31', '33/34', '34', '29']

nums.sort((a, b) => Number(a.split('/')[0]) - Number(b.split('/')[0]));

console.log(nums);

Now you may need to add more logic if you can have multiple numbers to push the 33/34 to the right spot. Not knowing all of the use cases, I am going to not try to guess.

CodePudding user response：

When converting to string your are converting the fraction 33/34 (=0.9705882352). That's all that's visible the JS interpreter: it does not matter whether you provided 0.9705882352 or 33/34 or 66/68. So as indicated by @ninascholz & @epascarello, you have to start off with strings. With strings, your code should work fine as in the demo below:

const nums = ['31', '33/34', '34', '29']

nums.sort((a, b) => a.localeCompare(b));

console.log( nums );