How do you get the next largest number, than a particular integer, in a list of integers?-CodePudding

Suppose a list [4,8,15,16,23,42]

Given the input value n, how do I find the minimum value in the above list that is greater than n, assuming n is not in the list? For example, 5 would yield 8, 17 would yield 23, 39 would yield 42, etc.

CodePudding user response：

You can sort the list, and then traverse the list for the next largest number. Try this:

li = [4, 8, 15, 16, 23, 42]
n = 5
li.sort()
for item in li:
    if item > n:
        print(item)
        break
# output: 8

CodePudding user response：

Say we have:

test_list = [9, 8, 7, 6, 5, 4, 3, 2, 1]
n = 5

First we can keep only numbers greater than n:

test_list_filtered = [a for a in test_list if a > n]
# resulting list: [9, 8, 7, 6]

Now we can just use min() to get the smallest item:

print(min(test_list_filtered))
# output: 6

Or, all on one line:

print(min([a for a in test_list if a > n]))
# Output: 6