How to make the output print the first position of every three identical numbers? (in this case 4 {position number 3} and 7 {position number 8)?

int counter = new int();
int[] arr = {1,2,3,4,4,4,5,6,7,7,7};
         
for (int i = 0; i < arr.Length; i  )
{
  if (arr[i] == arr[i 1]) // it says "Index was outside the bounds of the array."
  {
    counter  ;
    if (counter == 2)
    {
      Console.WriteLine(arr[i]   " "); 
    }
  }
}
Console.ReadKey();

CodePudding user response：

You must iterate through you array and check for equality 3 numbers in a row

int[] arr = { 1, 2, 3, 4, 4, 4, 5, 6, 7, 7, 7 };

for (int i = 0; i < arr.Length - 2; i  )
{
    if (arr[i] == arr[i   1] && arr[i] == arr[i   2])
    {
        Console.WriteLine("Trio is at:"   i   " Value is"   arr[i]);
    }
}

Console.ReadKey();