How to extract list of specific keys from the dictionary in Python?-CodePudding

I have a list of dictionaries that looks like that:

lst = [{'id': 'ID1', 'Name':'Name1', 'Surname':'Surname1'},
       {'id': 'ID2', 'Name':'Name2', 'Surname':'Surname2'},
       {'id': 'ID3', 'Name':'Name3', 'Surname':'Surname3'}]

I would like my output to look like that:

idnumber: ID1 ; Name: Name1 ; Surname: Surname1
idnumber: ID2 ; Name: Name2 ; Surname: Surname2
idnumber: ID3 ; Name: Name3 ; Surname: Surname3

As my strarting point, at least to start with id part, I wrote:

for l in lst:
    for key,value in l.items():
        if l.keys() == "id":
            print("idnumber: ", l.values())

Unfortunately, it doesn't work for me :( Any suggestion would be helpful.

CodePudding user response：

Here is an approach:

lst = [{'id': 'ID1', 'Name':'Name1', 'Surname':'Surname1'},
       {'id': 'ID2', 'Name':'Name2', 'Surname':'Surname2'},
       {'id': 'ID3', 'Name':'Name3', 'Surname':'Surname3'}]


keys = ['id', 'Name', 'Surname']
aliases = {'id': 'idnumber'}
for d in lst:
    for i, k in enumerate(keys):
        print(f'{aliases.get(k, k)}: {d[k]}',
              end=' ; ' if i 1<len(keys) else '\n')

output:

idnumber: ID1 ; Name: Name1 ; Surname: Surname1
idnumber: ID2 ; Name: Name2 ; Surname: Surname2
idnumber: ID3 ; Name: Name3 ; Surname: Surname3

How it works:

keys holds the list of keys to use in order
aliases holds the name of the key to print (aliases.get(k, k) searches for an alias and uses the key name if there is no alias)
enumerate allows to identify the last key to print a newline instead of the ; separator

CodePudding user response：

Iterate over the list of dictionaries and format each key-value pairs to finally join them together.

lst = [{'id': 'ID1', 'Name':'Name1', 'Surname':'Surname1'},
       {'id': 'ID2', 'Name':'Name2', 'Surname':'Surname2'},
       {'id': 'ID3', 'Name':'Name3', 'Surname':'Surname3'}]

for d in lst:
    print('; '.join(f"{k}: {v}" for k, v in d.items()))