Find a valor from list of dict-CodePudding

i have this list of dicts:

[{'campo': 'Admin_state', 'valor': 'enable'}, {'campo': 'LinkState', 'valor': 'enable'}, {'campo': 'ONU_interface', 'valor': 'gpon-onu_1/2/15:31'}, {'campo': 'Profile_type_Ont', 'valor': 'ZTE-F660V3'}]

i need to get the valor of 'campo:LinkState' that is in the position [1], but I can not get the value through the position because it varies... So, maybe can i do something like method .find in Js but in python?

something like this :

var statusOnt = data.find(data=>data.campo=='LinkState');

but in python. thanks

CodePudding user response：

Why don't you just iterate over the list?

for index, value in enumerate(my_list):
    if (value['campo'] == 'LinkState'):
        # index is the index you wanted
        break

To better understand my code I would suggest you to read enumerate docs.

If you want your code to be even more safe from KeyErrors and IndexErrors you can add a try/catch block:

try:
    if (value['campo'] ...):
        ...
except KeyError:
    continue

CodePudding user response：

Using filter and next:

l = [{'campo': 'Admin_state', 'valor': 'enable'},
     {'campo': 'LinkState', 'valor': 'enable'},
     {'campo': 'ONU_interface', 'valor': 'gpon-onu_1/2/15:31'},
     {'campo': 'Profile_type_Ont', 'valor': 'ZTE-F660V3'}]

out = next(filter(lambda d: d.get('campo', None)=='LinkState', l), {}
          ).get('valor', None)

output: 'enable'

This should return None if any key is missing or value is not found.

If you want to set a default value if no dictionary matches:

out = next(filter(lambda d: d.get('campo', None)=='LinkState', l),
           {'valor': 'default no match'}
           ).get('valor', 'default match but no defined value')