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Pandas groupby - Find mean of first 10 items

Time:05-24

I have 30 items in each group.

To find mean of entire items, I use this code.

y = df[["Value", "Date"]].groupby("Date").mean()

That returns a value like this.

Date                  Value
       
2020-01-01 00:30:00   7172.36
2020-01-01 01:00:00   7171.55
2020-01-01 01:30:00   7205.90
2020-01-01 02:00:00   7210.24
2020-01-01 02:30:00   7221.50

However, I would like to find the mean of the first 10 items in the group instead of the entire items.

y1 = df[["Value", "Date"]].groupby("Date").head(10).mean()

That code return only a single Value instead of a pandas series.

So I'm getting errors like this.

AttributeError: 'numpy.float64' object has no attribute 'shift'

What is the proper way to get the pandas series instead of a single value?

CodePudding user response:

You can try

y1 = df[["Value", "Date"]].groupby("Date").apply(lambda g: g['Value'].head(10).mean())
print(y1)

Date
2020-01-01 00:30:00    7172.36
2020-01-01 01:00:00    7171.55
2020-01-01 01:30:00    7205.90
2020-01-01 02:00:00    7210.24
2020-01-01 02:30:00    7221.50
dtype: float64

In .groupby("Date").head(10).mean(), groupby.head() returns the DataFrame, .mean() is operated on the whole DataFrame rather than the group.

CodePudding user response:

Try

# slice the first 10 and average
y1 = df.groupby("Date")["Value"].apply(lambda x: x.iloc[:10].mean())
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