How to pass multiple argments with process.startInfo.Arguments-CodePudding

I have this peace of code here:

void Main(string[] args) {
   string[] ARRAY = new string[2];
   ARRAY[0] = "1";
   ARRAY[1] = "2";
   
   Process process = new Process();
   process.startInfo.FileName = @"PATH"; //runs itself
   process.startInfo.Arguments = ARRAY;
   process.Start();
}

I need the program to pass whole array to next instance itsself (it is able to receive), but i keep getting that it requires string. Is there any workaround?

CodePudding user response：

process.startInfo.Arguments is of type string and you are trying to pass array of string to it.

public string Arguments { get; set; }

Instead of passing entire array, you have to convert it to the string first and then assign it to process.startInfo.Arguments

...
process.startInfo.Arguments = string.Join(" ", ARRAY);

Your final code will look like,

void Main(string[] args) {
   string[] ARRAY = new string[2];
   ARRAY[0] = "1";
   ARRAY[1] = "2";
   
   Process process = new Process();
   process.startInfo.FileName = @"PATH"; //runs itself
   process.startInfo.Arguments = string.Join(" ", ARRAY);
   process.Start();            //^^^^^^^^^^^^^^^ This is what you need
}

For more details: string.Join()

CodePudding user response：

startInfo.Arguments = "-sk server -sky exchange -pe -n CN=localhost -ir LocalMachine -is Root -ic MyCA.cer -sr LocalMachine -ss My MyAdHocTestCert.cer"