How to remove elements if they match in List?-CodePudding

When I click on the button, I need its name to be added to the List and when the button is clicked again, its name is added to the List again, but if 2 names match in the List, then they both need to be deleted. I tried to implement through the for loop but it does not work correctly for me. Tell me how can this be done?

function

List<String> types = [];

void reportButton(int number, String type) {
    reportsList[number] = !reportsList[number];
    if (reportsList.contains(true)) {
      isEnabledC = true;
    } else {
      isEnabledC = false;
    }

    types.add(type);

    for (var element in types) {
      if (element == type) {
        types.removeWhere((element) => element == type);
      }
    }

buttons

SizedBox(
              width: size.width / 3,
              child: GestureDetector(
                onTap: () {
                  cubit.reportButton(0, 'comment');
                  // state.type = 'comment';
                },
                child: ReportButton(
                  enabled: state.reports[0],
                  svg: constants.Assets.comment,
                  text: 'Comment',
                ),
              ),
            ),
            SizedBox(
              width: size.width / 3,
              child: GestureDetector(
                onTap: () {
                  cubit.reportButton(1, 'broken');
                  // state.type = 'broken';
                },
                child: ReportButton(
                  enabled: state.reports[1],
                  svg: constants.Assets.attention,
                  text: 'Broken station',
                ),
              ),
            ),

CodePudding user response：

you do not have to loop through the list of string. You can simply check if the list contains the string. If yes, remove it, else add the string

List<String> types = ["apple", "ball", "cat", "dog"];

void main() async {
  reportButton(1, "xyz");
}

void reportButton(int number, String type) {
    if (types.contains(type)) {
      types.removeWhere((element) => element == type);
    } else {
      types.add(type);
    }
  print(types);
}

CodePudding user response：

List<String> types = ["boy", "girl", "father", "hog"];

void main()  {
  reportButton(1, "xyz");
}
void reportButton(int number, String type) {
    if (types.contains(type)) {
      types.removeWhere((element) => element == type);
    }else {
      types.add(type);
    }
  print(types);
}