Convert ZipArchiveEntry to FileStream C#-CodePudding

I have a ZipArchiveEntry which is an Excel file and want to convert it to a FileStream. How can I do it? Also I don't have information about the path for the file. Basically this is the code I have:

   var zipArchive = new ZipArchive(InputStream);

   foreach (var entry in zipArchive.Entries)
   {
     using (var stream = entry.Open())
     {
       //Conversion stream => FileStream
     }
   }

CodePudding user response：

Stream.CopyTo - Reads the bytes from the current stream and writes them to another stream. Both streams positions are advanced by the number of bytes copied.

var zipArchive = new ZipArchive(InputStream);

foreach (var entry in zipArchive.Entries)
{
    using (var fileStream =  new FileStream(outputFileName, FileMode.Create))
    using (var stream = entry.Open())
    {
        stream.CopyTo(fileStream);
    }
}

CodePudding user response：

You can extract entries into temp folder and work with them.

const string tempFolder = ".temp";

var entryFileStreams = new List<FileStream>();

using (var archive = new ZipArchive(InputStream))
{
    // extracting excel files into temp folder
    foreach (ZipArchiveEntry entry in archive.Entries)
    {
        string destinationFileName = Path.Combine(tempFolder, entry.Name);

        FileStream entryFileStream = File.Create(destinationFileName);
        Stream entryStream = entry.Open();

        entryStream.CopyTo(entryFileStream);
        entryFileStreams.Add(entryFileStream);
    }
}

// work with FileStream's
foreach (FileStream entryStream in entryFileStreams)
{
    DoSomething(entryStream);
}

// disposing FileStream's
entryFileStreams.ForEach(entryStream => entryStream.Dispose());

// deleting entry temp files
Directory.Delete(tempFolder, true);