mlist = [["Rachel", -50],["Mawer", -50],["Sheen",-50],["Shaheen",51]]
list1 = []

x = sorted(mlist, key = lambda x : x[1])
print(x[1])

x = [x for x in x if x[x][1] != x[0][1]]
print(x)

def over1():
    for i in range(4):
        if x[i][1] == x[0][1]:
            list1.append(x[i][0])
        
    list1.sort()
    print(*list1, sep="\n")

over1()

I am trying to delete all variables which have minimum of the second element of each value in the list and I wanted to make it happen with using x. (print(x) for control purposes)

In the line x = [x for x in x if x[x][1] != x[0][1]] compiler gives me the error "list indices must be integers or slices, not list".

Is it possible with using x only and where is my mistake?

CodePudding user response：

I'm not sure if a complete one-liner would be considered good programming, but I managed to do this in 2 lines by using list comprehension. I first find the minimum value and then use that to produce a resultant list that does not contain the minimum value:

mlist = [['Rachel', -50], ['Mawer', -50], ['Sheen', -50], ['Shaheen', 51]]

min_val = min([a[1] for a in mlist])
x = [a for a in mlist if a[1] != min_val]

print(*x, sep='\n')

Output:

['Shaheen', 51]

CodePudding user response：

x = [x for x in x if x[x][1] != x[0][1]]

First of: this code line is a little hard to read. Second: you're basically trying to iterste over an a list of x, and then assign value of x[0] to it in

for x in x

Third: you iterating over list of lists, so you cant use x[x] because x is equal to ["Rachel": -50]. Fourth: python is interpreter, not compiler, you may want to keep that in mind for later learning of the language