Problem is finding second highest values in vb.net-CodePudding

Aim: To find the second smallest value of the sorted array in VB.NET. Procedure: Step 1: Start the program. Step 2: Assign input values for an Array. Step 3: sort the input of an array by using Sort method. Step 4: Find the second smallest value of the sorted array . Step5: show the sorted array and second smallest value of an array. Step6: stop the program '''Module Module1

Sub Main()
    Dim n(10) As Integer 'Declaration n in array in integer format'
    Dim i, j As Integer  'Declaration i,j in integer format'
    Dim second_small As Integer
    second_small = 0
    Dim small As Integer
    small = 0
    For i = 0 To 10 'first condition check the statement looping for the 10 time'
        Console.WriteLine(" Enter the value for array value[{0}] : ", i)  'user input array values'
        n(i) = Console.ReadLine()  ' store the values in n of arry' 
    Next i
    For j = 0 To 10 'for array number'
        Console.WriteLine("Array value({0}) = {1}", j, n(j))
    Next j
    Console.WriteLine("Lowest Number To Higher Number")
    System.Array.Sort(n)
    For Each str As Integer In n
        Console.WriteLine(str)
    Next
    small = n(-1)
    For i = 1 To 10 Step 1
        If (small > n(i)) Then
            second_small = small
            small = n(i)
        End If
    Next
    Console.WriteLine("Second smallest element in array is: {0}", second_small)
    Console.ReadKey()
End Sub

CodePudding user response：

If you sort the array, you can select the first two elements after sorting. A more efficient way (arguably) is what you're trying to do with the last loop, which is not quite correct as it stands now.

CodePudding user response：

the answer is Console.WriteLine("Second smallest element in array is: {0}", n(1)) array values are stored in n values so the second smallest values are stored in 1 area