Sum list elements when sum is not greater than given interval, else skip element-CodePudding

I have a list of numbers and I need to get some of these, but: list element should be skipped if sum this element is bigger or smaller than given numbers in interval. I try to do continue within for loop, but smth is wrong and I do not understand what. How can I do this in correct way? Thanks in advance

I tried this (sum should start from 1)

numbers = [3,2,-3,-1,5,7,-1,-2]
interval = [-1,0,1,2,3,4,5,6,7,8,9]
sum = 1

for i in range(0,len(numbers)):
    sum = sum   numbers[i]
    if sum not in interval:
        continue
    print(sum)

So,

    1 3 2=6 <- its ok
    6 (-3) = 3 <- its ok
    3 (-1) = 2 <- its ok
    2  5 = 7 ok

7 7 = 14 <- thats not ok

because 14 is not in interval. So if its not in interval loop should skip 7 value and goes to -1 value.

CodePudding user response：

Your question is a bit unclear. But right now you are doing these steps:

go through each element in numbers
add next element to sum
check if sum is in not in interval
if true continue
print sum

To me it is usually easier to think the other way, if it is in interval then I want something to happen. As I understood your question is that you want to print these numbers:

4 6 3 2 7 6 4

This code should do the trick:

numbers = [3,2,-3,-1,5,7,-1,-2]
interval = [-1,0,1,2,3,4,5,6,7,8,9]
sum = 1

for i in range(0,len(numbers)):
    if (sum   numbers[i]) in interval:
        sum = sum   numbers[i]
        print(sum)

But if you want to do your logic, if would put the adding inside an else like this:

numbers2 = [3,2,-3,-1,5,7,-1,-2]
interval2 = [-1,0,1,2,3,4,5,6,7,8,9]
sum2 = 1

for j in range(0,len(numbers2)):
    if sum2   numbers2[j] not in interval2:
        continue
    else:
        sum2 = sum2   numbers2[j]
        print(sum2)

CodePudding user response：

numbers = [3,2,-3,-1,5,7,-1,-2]
interval = [-1,0,1,2,3,4,5,6,7,8,9]
sum = 1

for i in range(0,len(numbers)):
    if sum in interval:
        sum = sum   numbers[i]
        print(sum)