Ruby Remove Array in Array when One Item is Nil or ""-CodePudding

In Ruby, I am trying to display items that are in an array of arrays if both items in the array are present. For example: [["ABC Inc", "This is a test"], ["XYZ Inc", "This is a second test"], ["EFG Inc", ""]]

When displaying this array on the front end, I would like to display the first set and second set, but not display the third: EFG Inc, as it is missing the second item in the array.

The front end currently displays:

ABC Inc: This is a test

XYZ Inc: This is a second test

EFG Inc:

CodePudding user response：

In Ruby I would use Array#select to only pick those nested arrays that have all elements being present, like this:

nested_array = [["ABC Inc", "This is a test"], ["XYZ Inc", "This is a second test"], ["EFG Inc", ""]]
nested_array.select { |array| array.none?(&:empty?) }
#=> [["ABC Inc", "This is a test"], ["XYZ Inc", "This is a second test"]]

See Array#none? and String#empty?

In Ruby on Rails, you can also use Array#all? and Object#present? which reads nicer and also covers nil elements:

nested_array = [["ABC Inc", "This is a test"], ["XYZ Inc", "This is a second test"], ["EFG Inc", ""]]
nested_array.select { |array| array.all?(&:present?) }
#=> [["ABC Inc", "This is a test"], ["XYZ Inc", "This is a second test"]]