From an array, find the array that has the true values for the objects-CodePudding

Given array: const array = [{1: true},{2: false},{3: true},{}.....];

Filter the given array by only including objects with values of true.

Looking for the shortest solution.

CodePudding user response：

const onlyTrue = array.filter((el, ind) => el[ind   1] === true);

This will work only if indexes in array objects are ordered and starting from 1, as it is in your example.

CodePudding user response：

Assumptions (based on what's in your example):

Each object in the array only has at least 1 property in it
The first property on each object is the one we care about
The property in each object is different every time

const array = [{1: true},{2: false},{3: true}];
const results = array.filter(item => Object.values(item)[0]);

If you want to avoid any false positives from truth-y values (see https://developer.mozilla.org/en-US/docs/Glossary/Truthy), then change the filter call to this instead:

const results = array.filter(item => Object.values(item)[0] === true);

CodePudding user response：

const array = [{1: true},{2: false},{3: true}];
const array2 = [];
array.forEach(filterTrue);
function filterTrue(item){
    for(x in item){
        if(item[x]===true){
            array2.push(item);
        }
    }
}
console.log(array2);

Hope this helps you.