loop in the nested dictionary-CodePudding

I have a nested dictionary. Sometimes it contains more than two attachments. How can I loop through the dictionary to get the following values in the variables ?

dict = {'result': [{'a1': 'one', 'a2': 'two', 'a3': '2'},
                  {'b1': 'three', 'b2': 'one', 'b3': '5'}]}

 res1 = one
 res2 = two
 res3 = 2

 res1 = three
 res2 = one
 res3 = 5

CodePudding user response：

If you want to store each value in different variable then I would suggest to append those values in a list.

The code to access those values are:

dictt = {'result': [{'a1': 'one', 'a2': 'two', 'a3': '2'},
              {'b1': 'three', 'b2': 'one', 'b3': '5'}]}
for key, value in dictt.items() :
    for i in range(2):
        for item in value[i].values():
            print(item)

The ouptut of this is:

one
two
2
three
one
5

CodePudding user response：

dict1 = {'result': [{'a1': 'one', 'a2': 'two', 'a3': '2'},{'b1': 'three', 'b2': 'one', 'b3': '5'}]}
for j in dict1['result']:
    print([(j[k]) for k in j])

please don't give dict as dictionary name. output:

['one', 'two', '2']
['three', 'one', '5']

to assign the values, refer this code:

dict1 = {'result': [{'a1': 'one', 'a2': 'two', 'a3': '2'},{'b1': 'three', 'b2': 'one', 'b3': '5'}]}
l=[]
l1={}
for j in dict1['result']:
    s=[(j[k]) for k in j]
    l.append(s)
for z in range(3):
    key=str("res" str(z))
    l1[key]=[l[0][z], l[1][z]]

print(l1)

you will get this as output:

{'res0': ['one', 'three'], 'res1': ['two', 'one'], 'res2': ['2', '5']}