Split file based on the number of X symbol on each line-CodePudding

I'm not sure if this is possible, but I'm wondering if it'd be able to split a file into multiple files - dependent on the amount of a specified character there is on each line.

Lets use a colon (:) as an example

File.txt contains the following data (example):

Stack:Overflow   
Stack:Overflow:Flow    
Stack:Over:Flow:Com

Entire line containing 1 colon, goes to 1.txt
Entire line containing 2 colons, goes to 2.txt
Entire line containing 3 colons, goes to 3.txt

(And of course) there wouldn't be a limit to the amount of colons, and format may not necessarily always match the exampled pattern.

Sorry if this is a vague question, I'm first time posting on StackOverflow in a long.

Another side question: Inserting a specific character between 2 different regexs.

Data:

[email protected]

I'm trying to insert a delimiter which will be ":"
Between 2 different regexes.
Regex #1 being: [A-Za-z0-9._% -] @[A-Za-z0-9.-] \.[A-Za-z]{2,6}
Regex #2 being: [0-9]{1,4}\.[0-9]{1,4}\.[0-9]{1,4}\.[0-9]{1,4}

So the desired output would be:

[email protected]:192.168.0.1

CodePudding user response：

With GNU AWK this approach will provide your expected outcome:

awk -F":" '{print > ((NF - 1)".txt")}' file.txt

NB. if you have a large number of delimiters (hundreds - thousands) you may also run into trouble for having too many open files (I believe ulimit -n will tell you how many different files you can have open at one time; on my system it's 256)

CodePudding user response：

awk can do this quite easily:

awk -F : '{print > NF-1".txt"}' File.txt

With : as a field separator, the number of fields (NF) minus one is equal to the number of field separators. Which we can use for the file name.
You can replace the colon with any character, except space, which must be written as [ ]. Otherwise awk handles it specially.
Field separator is normally a regular expression, except, if it's a single character it's treated literally (except space).