Modify Curl output-CodePudding

I am saving the information of a curl in a variable. The output is as follows:

INFOISP=$(curl --silent ipinfo.io | grep -E '"ip"|"hostname"|"region"|"country"|"org"')

The output is this:

  "ip": "186.152.174.190",
  "hostname": "host190.186-152-174.telecom.net.ar",
  "region": "Santa Fe",
  "country": "AR",
  "org": "AS7303 Telecom Argentina S.A.",

I need this:

"ip": "186.152.174.190" 
"hostname": "host190.186-152-174.telecom.net.ar" 
"region": "Santa Fe" 
"country": "AR" 
"org": "AS7303 Telecom Argentina S.A."

I try with sed using this:

INFOISP=$(curl --silent ipinfo.io | grep -E '"ip"|"hostname"|"region"|"country"|"org"')
echo ${INFOISP} | sed -e $'s/,/\\\n/g'

but the output is not in the same column:

  "ip": "186.152.174.190"

  "hostname": "host190.186-152-174.telecom.net.ar" 

  "region": "Santa Fe" 

  "country": "AR" 

  "org": "AS7303 Telecom Argentina S.A."

any helps?

CodePudding user response：

The output of your curl command is a well formatted JSON so you could use jq for extracting data from it robustly. For what you're trying to do you can use other tools though, for ex. GNU grep:

curl --silent ipinfo.io |
grep -oE '("ip"|"hostname"|"region"|"country"|"org"): "[^"]*"'

CodePudding user response：

You could do the filtering within sed skipping the need for grep

$ infoisp=$(curl --silent ipinfo.io | sed -En '/ip|hostname|region|country|org/{s/[^"]*([^,]*).*/\1/p}')
$ echo "$infoisp"
"ip": "186.152.174.190"
"hostname": "host190.186-152-174.telecom.net.ar"
"region": "Santa Fe"
"country": "AR"
"org": "AS7303 Telecom Argentina S.A."