I have a Mongo database with multiple documents and they all contain 2 Items for in store and online locations. The difference will be that attributes within the items object may differ. I am trying to capture all documents that have differing attributes between the object items with the array.
I've tried using $expr and comparing the position of the elements such as "Items.0.Attributes" == "Items.1.Attributes" but had no luck.
{
"ID" : "123456789",
"Items" : [
{
"ItemDept" : "softLines",
"ProductId" : {
"Name" : "shirts",
"_id" : "12345Shirts"
},
"Attributes" : [ "blue","small","mens"],
"Season" : "Summer"
"Location":"online"
}
,
{
"ItemDept" : "softlines",
"ProductId" : {
"Name" : "shirts",
"_id" : "12345Shirts")
},
"Attributes" : [ "blue","small","women"],
"Season" : "Summer"
"Location":"stores"
}
]
}
CodePudding user response:
If I understand what you want to find
/output, here's one way you could do it.
db.collection.find({
"$expr": {
"$not": {
"$setEquals": [
{"$first": "$Items.Attributes"},
{"$last": "$Items.Attributes"}
]
}
}
})
Try it on mongoplayground.net.