Is there any way to get more debug info from gdb?-CodePudding

I can get more debug info if built my program on Windows compared to Linux. Here is my code:

#include <iostream>
#include <vector>

using namespace std;

class Base
{
public:
    Base() = default;
    virtual ~Base() = default;
};

class Derived : public Base
{
public:
    Derived() = default;
    ~Derived() = default;
private:
    int i = 1;
};

int main()
{
    vector<Base*> a;
    a.push_back(new Derived());
    return 0;
}

Build On Linux:

Build On Windows:

It's obvious I can get more information with Windows build version. Such as vector info, vector element real type, derived object info... But Linux version, I only get the pointer address. By the way, they are all debugging by visual studio. Is there some way to add more debug info to the program built by GNU compiler? Such as compiler flags?

CodePudding user response：

I don't use visual studio, so not sure how you will make use of this answer from within that environment, however, I think you can get what you want using the GDB setting: set print object on.

To show this in action, here's my GDB (12.1) session, using the same test program that you posted:

$ gdb -q vec.x
Reading symbols from vec.x...
(gdb) b 26
Breakpoint 1 at 0x401245: file vec.cc, line 26.
(gdb) r
Starting program: /tmp/vec.x 

Breakpoint 1, main () at vec.cc:26
26      return 0;
(gdb) p a
$1 = std::vector of length 1, capacity 1 = {0x418eb0}
(gdb) p a[0]
$2 = (Base *) 0x418eb0
(gdb) p *a[0]
$3 = {
  _vptr.Base = 0x403040 <vtable for Derived 16>
}
(gdb) set print object on 
(gdb) p a[0]
$4 = (Derived *) 0x418eb0
(gdb) p *a[0]
$5 = (Derived) {
  <Base> = {
    _vptr.Base = 0x403040 <vtable for Derived 16>
  }, 
  members of Derived:
  i = 1
}
(gdb) q

CodePudding user response：

I fixed this problem by add a init command to the ~/.gdbinit.

Add the following command to the first line of file ~/.gdbinit.

set print object on