So if x = Number value background
changes fine, my question is when x has no value. How can I have a background-color
of #ffffff
. Currently, code is defaulting to #db0000
.
JS:
var grid_value = document.getElementById("Vone").innerHTML;
var x = grid_value;
if (x >= 0 && x < 15) {
document.getElementById("GridA").style.backgroundColor = "#db0000";
} else if (x >= 15 && x < 25) {
document.getElementById("GridA").style.backgroundColor = "#f0ad4e";
} else if (x >= 25) {
document.getElementById("GridA").style.backgroundColor = "#5cb85c";
} else if (x = "Pick" ) {
document.getElementById("GridA").style.backgroundColor = "#0085eb";
} else if (x = "" ) {
document.getElementById("GridA").style.backgroundColor = "#ffffff";
}
CodePudding user response:
Here you haven't given any conditions if x doesn't have a value, so the default condition is x=0. You should try else if (!x).
else if (!x) {
document.getElementById("GridA").style.backgroundColor = "#ffffff";
}
Hope this helps you out.
CodePudding user response:
const gA = document.getElementById("GridA");
document.getElementById("Vone").addEventListener("blur", function(event){
gA.classList = "";
var x = this.value;
if (x === "") {
gA.classList.add("white");
} else if (x === "Pick") {
gA.classList.add("color1");
} else if (x >= 0 && x < 15) {
gA.classList.add("color2");
} else if (x >= 15 && x < 25) {
gA.classList.add("color3");
} else if (x >= 25) {
gA.classList.add("color4");
}
});
#GridA { height:100px; border:1px solid grey; margin-top:5px; }
.color1 { background-color:#dbf000; }
.color2 { background-color:#f0ad4e; }
.color3 { background-color:#5cb85c; }
.color4 { background-color:#0085eb; }
.white { background-color:#ffffff; }
<input id="Vone">
<div id="GridA"></div>