How to pass struct variable to function as argument or reference in C?-CodePudding

I want to pass a struct variable as a function parameter (sorry for bad English.) Here is what I want to do:

#include <stdio.h>
#include <stdint.h>

typedef struct {
  int temp;
  int hum;
  int oxy;
} Data;

Data sens1;
Data sens2;
Data sens3;

sens1.temp = 5;
sens2.temp = 10;
sens3.temp = 15;


int ort(Data temp1 , Data temp2 , Data temp3)
{
  int ort = ((temp1   temp2   temp3) / 3);
  return ort;
}

int main(void)
{
  printf("%d", ort(sens1.temp, sens2.temp, sens3.temp));
  return 0;
}

How to add struct member called temp to function ort() as parameter?

CodePudding user response：

You cannot add structs, and that's what you are doing in temp1 temp2 temp3.

You probbaly want this:

int ort(Data sensor1 , Data sensor2, Data sensor2)
{
  int ort = ((sensor1.temp   sensor2.temp   sensor2.temp) / 3);
  return ort;
}
...
printf("%d" , ort(sens1, sens2, sens3);
...

or this:

int ort(int temp1, int temp2, int temp3)
{
  int ort = ((temp1   temp2   temp3) / 3);
  return ort;
}
...
printf("%d" , ort(sens1.temp, sens2.temp, sens3.temp);
...

CodePudding user response：

If you want to pass a reference to the struct rather than the whole struct, the typical method is something like:

#include <stdio.h>
#include <stdint.h>

struct data {
        int temp;
        int hum;
        int oxy;
};

struct data sens1 = { .temp = 5 };
struct data sens2 = { .temp = 10 };
struct data sens3 = { .temp = 15 };


float
ort(const struct data *d1, const struct data *d2, const struct data *d3)
{
        return (float)(d1->temp   d2->temp   d3->temp) / 3;
}

int
main(void)
{
        printf("%f\n", ort(&sens1, &sens2, &sens3));
        return 0;
}