My BASH scrit has following line:
video_id=$(/usr/local/bin/yt-dlp --no-warnings --get-id "$ChannelPath")
it succeeds when runs from command line under certain user.
When it runs from cron, under the same user, it results in:
/usr/bin/env: python3: No such file or directory
What could be different in these two cases?
- CentOS 7
- Python 3.11.0a4
CodePudding user response:
There are some discussions whether you should use #!/usr/bin/env python
or #!/usr/bin/python
. Proponents of the env
variant say that it is better, because env
uses the PATH
to find the interpreter, and opponents say that the problem with the env
variant is that it uses the PATH
.
I dislike env
, therefore I will give you a solution without it.
From the command line type
which python3
This will give you something like
/usr/bin/python3
In /usr/local/bin/yt-dlp
, replace the first line with
#!/usr/bin/python3
(the output that you got from the which
command.)
Or call /usr/local/bin/yt-dlp
with explicitly the right interpreter:
video_id=$(/usr/bin/python3 /usr/local/bin/yt-dlp --no-warnings --get-id "$ChannelPath")
CodePudding user response:
it succeeds when runs from command line under certain user.
When it runs from cron, under the same user, it results in:
/usr/bin/env: python3: No such file or directory
What could be different in these two cases?
The difference is the environment in which the script runs. In particular, the environment variables in it, and most particularly, the PATH
.
When a user runs the script from the command line, it inherits the environment from which it was launched, which includes system-wide and possibly user-specific customizations that are engaged only for interactive shells. (For example, the contents of the user's ~/.bash_profile
and / or ~/.bashrc
files.) By default, when a shell is launched noninteractively (by cron
, for example) it does not read or execute any environment configuration.
Evidently,
Your
/usr/local/bin/yt-dlp
is or attempts to launch a Python script that has a shebang line using/usr/bin/env
to choose and launch thepython3
binary. That is, the affected script starts with#!/usr/bin/env python3
These days, that form is widely used and recommended in the Python world. The purpose is to use the
PATH
to locate thepython3
binary to use, as opposed to hard-coding that into the script. However,There is no system Python 3 installed on the machine. (That is, none installed in the default path.) The user who runs the script successfully is able to do so because they have an environment configured with some non-default directory in their
PATH
from whichpython3
can be launched.
One possible solution would be to install CentOS's Python 3:
sudo yum install python3
If you need a different version of Python 3 (CentOS 7's is version 3.6) then you can instead set an appropriate PATH
in the relevant crontab
file, maybe something like
PATH=/usr/local/bin:/usr/bin:/bin:/usr/sbin:/sbin
0 * * * * /path/to/my_script
Alternatively, you could modify your shell script to set the path there:
PATH=/usr/local/bin:$PATH
video_id=$(/usr/local/bin/yt-dlp --no-warnings --get-id "$ChannelPath")
or you could modify /usr/local/bin/yt-dip
by altering its shebang (supposing that this is the affected Python script).
CodePudding user response:
I moved the python3
symlink from /usr/local/bin
to /usr/bin
and it works now.
/usr/local/bin
was the suggested location in internet-manuals about how to compile and install Python 3.11 in CentOS7.
A better solution is to add
PATH=/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/root/bin
to the first line of crontab. Although it should be not /etc/crontab
, but
crontab -l > crontab.txt
then edit crontab.txt
then
crontab crontab.txt