Input: The output from my current jq filters looks like

{
  "id1": {
    "version": 4,
    "lastModifier": "abc"
  }
}
{
  "id2": {
    "version": 3,
    "lastModifier": "def"
  }
}
{
  "id3": {
    "version": 8,
    "lastModifier": "abc"
  }
}

Desired Output: I just need to wrap this list in a object so I end up with

{
  "ref": {
      "id1": {
          "version": 4,
          "lastModifier": "abc"
      },
      "id2": {
          "version": 3,
          "lastModifier": "def"
      },
      "id3": {
          "version": 8,
          "lastModifier": "abc"
      }
   }
}

I don't want to merge anything from the input list into the output object, all the properties need to remain as-is, so piping to add doesn't work. Also tried wrapping my filters with { "ref": ( filters )} but that yields the same list with a "ref" wrapper for each object. Possibly reduce is what is needed but haven't been able to construct that appropriately.

CodePudding user response：

Use the -s flag to read the stream into an array, the add it up and put it into your object:

jq -s '{ref: add}'

{
  "ref": {
    "id1": {
      "version": 4,
      "lastModifier": "abc"
    },
    "id2": {
      "version": 3,
      "lastModifier": "def"
    },
    "id3": {
      "version": 8,
      "lastModifier": "abc"
    }
  }
}

Demo

Of course, there is also a solution using reduce:

jq -n 'reduce inputs as $in ({}; .ref  = $in)'

{
  "ref": {
    "id1": {
      "version": 4,
      "lastModifier": "abc"
    },
    "id2": {
      "version": 3,
      "lastModifier": "def"
    },
    "id3": {
      "version": 8,
      "lastModifier": "abc"
    }
  }
}

Demo