Countdown the chances in loop for guessing game-CodePudding

I made five chances for the guesser to guess the random number. Every time the guesser did wrong, I want to print:

Nice try, guess again (try bigger), you get {x} chance left.

The x is a countdown, so the first wrong guess will say you get 4 chances left, then another wrong, three chances left, and so on. How can I do that? Or, how to add a loop on the x.

So this is my unsuccessful code:

import random

secret_num = random.randint(1, 20)

print('Guess the number from 1-20 (you get 5 chances)')

for guess_chance in range(1, 6):
    guess = int(input("Input guess number: "))

    if guess < secret_num:
        x = 5
        x -= 1
        print(f'Nice try, guess again (try bigger), you get {x} chance left.')

    elif guess > secret_num:
        x = 5
        x -= 1
        print(f'Nice try, guess again (try smaller), you get {x} chance left.')

    else:
        break

if guess == secret_num:
    print('Congratz, you guess correctly in'   str(guess_chance)   'times.')
else:
    print('Nope, the correct number is '   str(secret_num)   '.')

CodePudding user response：

You need to do x = 5 before for guess_chance in range...) and remove it from inside the loop.

print('Guess the number from 1-20 (you get 5 chances)')

x = 5

for guess_chance in range(1, 6):
    guess = int(input("Input guess number: "))

    if guess < secret_num:
        x -= 1
        print(f'Nice try, guess again (try bigger), you get {x} chance left.')

    elif guess > secret_num:
        x -= 1
        print(f'Nice try, guess again (try smaller), you get {x} chance left.')

    else:
        break

Otherwise, each guess you are resetting it to 5 tries and then subtracting one... which presumably always shows 4 tries...

There are many other ways to solve this... I just picked the one that changed your code the least

and when combined with your range this is a bit redundant

x = 6 - guess_chance would work

as would just iterating the range in reverse