Counting how many dozen in a number and also count its extra amount?-CodePudding

How do i make this program counts how many dozen in a number and also count its extra amount? This is what only I came up

#include<stdio.h>

int main()

{

float number, dozen;

printf("Please Enter any integer Value : ");

scanf("%f", &number);

dozen = number / 12;

printf("dozen of a given number %.2f is  =  %.2f", number, dozen);

return 0;

}

I dont know how i will get to count the dozen in a number, for example there is 45, i need to get 3 dozen and the extra will be 9.

CodePudding user response：

You prompt for an integer but then use floats. You already had the correct dozen calculation and just miss the modulo operator %. Reformatted code for readability.

#include <stdio.h>

int main() {
    printf("Please Enter any integer Value : ");
    int number;
    scanf("%d", &number);
    printf("dozen of a given number %d is %d with remainder %d\n",
        number,
        number / 12,
        number % 12
    );
    return 0;
}

and example execution:

Please Enter any integer Value : 14
dozen of a given number 14 is 1 with remainder 2

CodePudding user response：

Now that there is an accepted answer,
here's a small lesson in arithmetic (plagiarising @Allan Wind's answer):

#include <stdio.h>

int main() {
    printf("Please Enter any integer Value : ");
    int number;
    scanf("%d", &number);
    printf("dozen of a given number %d is %d with remainder %d\n",
        number,
        number / 12,
        number - number / 12
    );
    return 0;
}