I'm using React's Strict mode, and I'm having a useEffect
that is causing me some headaches. Part of React's Strict mode is that those things can fire twice, so I'm writing code to protect myself from that.
However I seem to be missing something when using useReducer
. By using useState
I'm able to update the state so that useEffect
becomes idempotent.
With useReducer
I dispatch an action which only seems to be executed AFTER useEffect
has rendered twice, effectively nullifying my idempotency.
useState
example (pardon the React setup cruft, StackOverflow doesn't support React 18 natively):
const { StrictMode, useState, useEffect } = React;
const root = ReactDOM.createRoot(document.getElementById("root"));
root.render(
<StrictMode>
<WithUseState />
</StrictMode>
);
function WithUseState() {
const [counter, setCounter] = useState(0);
useEffect(() => {
if (counter === 0) {
setCounter(counter 1);
}
}, [counter]);
return <React.Fragment>{counter}</React.Fragment>;
}
<div id="root"></div>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/18.2.0/umd/react.development.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react-dom/18.2.0/umd/react-dom.development.js"></script>
useReducer
example, where the order seems to be: useEffect
, useEffect
, resolve dispatch
, resolve dispatch
:
const { StrictMode, useEffect, useReducer } = React;
const root = ReactDOM.createRoot(document.getElementById("root"));
root.render(
<StrictMode>
<WithUseReducer />
</StrictMode>
);
function reducer(state, action) {
switch (action.type) {
case "increment":
return { ...state, counter: state.counter 1 };
default:
throw new Error();
}
}
function WithUseReducer() {
const [state, dispatch] = useReducer(reducer, { counter: 0 });
useEffect(() => {
if (state.counter === 0) {
dispatch({ type: "increment" });
}
});
return <React.Fragment>{state.counter}</React.Fragment>;
}
<div id="root"></div>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/18.2.0/umd/react.development.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react-dom/18.2.0/umd/react-dom.development.js"></script>
CodePudding user response:
You can use the production build of React. useEffect
running twice was added in React 18: https://reactjs.org/docs/strict-mode.html#ensuring-reusable-state
const { StrictMode, useEffect, useReducer } = React;
const root = ReactDOM.createRoot(document.getElementById("root"));
root.render(
<StrictMode>
<WithUseReducer />
</StrictMode>
);
function reducer(state, action) {
switch (action.type) {
case "increment":
return { ...state, counter: state.counter 1 };
default:
throw new Error();
}
}
function WithUseReducer() {
const [state, dispatch] = useReducer(reducer, { counter: 0 });
useEffect(() => {
if (state.counter === 0) {
dispatch({ type: "increment" });
}
});
return <React.Fragment>{state.counter}</React.Fragment>;
}
<div id="root"></div>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/18.2.0/umd/react.production.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react-dom/18.2.0/umd/react-dom.production.min.js"></script>
CodePudding user response:
In react 18, useEffect
will be called twice in Strict Mode
This happens only in development mode not in production mode . to prevent this behavior in development mode you can use a custom hook instead of useEffect
.
export const useEffectOnce = (effect) => {
const destroyFunc = useRef();
const effectCalled = useRef(false);
const renderAfterCalled = useRef(false);
const [val, setVal] = useState(0);
if (effectCalled.current) {
renderAfterCalled.current = true;
}
useEffect(() => {
// only execute the effect first time around
if (!effectCalled.current) {
destroyFunc.current = effect();
effectCalled.current = true;
}
// this forces one render after the effect is run
setVal((val) => val 1);
return () => {
// if the comp didn't render since the useEffect was called,
// we know it's the dummy React cycle
if (!renderAfterCalled.current) {
return;
}
if (destroyFunc.current) {
destroyFunc.current();
}
};
}, []);
};
check this codesandbox (it is using you example but firing just once )
CodePudding user response:
You could add a cleanup function to your useEffect that resets the state when unmounted (because React 18 mounts, then unmounts, then mounts again).
(The isMounted state is only needed if state should be persistent between views/different component renders).
const { StrictMode, useEffect, useReducer } = React;
const root = ReactDOM.createRoot(document.getElementById("root"));
root.render(
<StrictMode>
<WithUseReducer />
</StrictMode>
);
function reducer(state, action) {
switch (action.type) {
case "increment":
return { ...state, counter: state.counter 1 };
case "mount-reset":
if (!state.isMounted)
return { ...state, counter: 0, isMounted: true };
default:
throw new Error();
}
}
function WithUseReducer() {
const [state, dispatch] = useReducer(reducer, { counter: 0 });
useEffect(() => {
if (state.counter === 0) {
dispatch({ type: "increment" });
}
return () => dispatch({ type: "mount-reset" });
}, []);
return <React.Fragment>{state.counter}</React.Fragment>;
}
<div id="root"></div>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/18.2.0/umd/react.development.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react-dom/18.2.0/umd/react-dom.development.js"></script>
See these for further explanations:
Bug: useEffect runs twice on component mount (StrictMode, NODE_ENV=development)