the number of days between two string-type dates-CodePudding

i iam trying to fing the number of dates between a given dat and todays date. given date: 2022-10-10T09:01:38.581210Z

todays date: i ran this code:

from datetime import datetime
now = datetime.now()
    # dd/mm/YY H:M:S
    dt = now.strftime("%Y-%m-%d"   "T"   "%H:%M:%S"   "Z")

my output for todays date: 2022-10-11T08:29:36Z

i am trying to get the number of days between these two dates. they are both strings and i can not perform simple subtraction. please help

CodePudding user response：

It seems you have trouble converting your past date 2022-10-10T09:01:38.581210Z from string to a datetime object, is that right?

You shall set you format right:

from datetime import datetime
past_date = datetime.strptime("2022-10-10T09:01:38.581210Z", "%Y-%m-%dT%H:%M:%S.%fZ")
print(datetime.now() - past_date)

Output:

1 day, 1:41:12.762025

You can return the number of elapsed days as integer with print((datetime.now() - past_date).days)

CodePudding user response：

you can do it with out convert your datetime to string

(given_date - now).days # will give you number of days between dates

given_date and now are both datetime Object

CodePudding user response：

You should do something like this is better i think, you import module datetime and then we substract the two dates and we get how many days.

from datetime import date
 
def numOfDays(date1, date2):
    return (date2-date1).days
     
# Driver program
date1 = date(2018, 12, 13)
date2 = date(2019, 2, 25)
print(numOfDays(date1, date2), "days")

CodePudding user response：

import datetime
your_date =  '2022-09-01'
i =1
while(True):
  d = today - datetime.timedelta(days=i)
  i = i 1
  if ( str(d) == your_date ):
    break

print(i)

CodePudding user response：

From your data, by applying the correct corresponding format template and setting up the UTC timezone to the method datetime.now, we can convert the strings in datetime format :

from datetime import datetime, timezone

dt_1 = datetime.now(timezone.utc)
dt_2 = datetime.strptime("2022-10-10T09:01:38.581210Z", "%Y-%m-%dT%H:%M:%S.%f%z")

Then, a substraction with the days attribute allow us to get the expected result :

(dt_1 - dt_2).days