I would like to create the graphic of a truss. I have two lists of lists; one gives the bar number and the nodes that make them, it looks like this:

elements = [[1, 1, 2], [2, 2, 3], [3, 3, 4], [4, 4, 5], [5, 5, 1], [6, 1, 4], [7, 2, 4], [8, 4, 6], [9, 6, 5]]

For example, element one is composed by node 1 and node 2. The other dataset gives the nodes followed by its coordinates in the 2D plane. It looks like this:

nodes= [[1.0, 0.0, 1.2], [2.0, -1.5, 1.2], [3.0, -1.5, 0.0], [4.0, 0.0, 0.0], [5.0, 1.5, 1.2], [6.0, 1.5, 0.0]]

For example, node 1 has the (0.0, 1.2) coordinates.

I want to recreate with pyplot the following graphic using the lists of list above. Where A is 1.5m and B 1.2m.

I thought doing something like this:

def draw(nodes):
    draw1=[]
    for i in range(len(nodes)):
        for j in range(len(nodes[1])):
            mmc =[(nodes[i][j][1][1],nodes[i][j][1][2])]
    for t in [draw1]:
        xs1, ys1 = zip(*t)
        plot(xs1, ys1, 'o')
        plot(xs1, ys1, '-')
    plot.show()

I know I am not doing the for right (out of index) but I don´t really know how to solve it.

CodePudding user response：

Your question is too wide, I provide an answer only to the first part of it, given a list of nodal coordinates and a list of connectivities, how to draw a truss?

First, you are going to use a dataclass and store much more info about each one of the bars, but as a starter I have

In [8]: class Bar():
   ...:     def __init__(self, i, j):
   ...:         self.i = i
   ...:         self.j = j

Next, a list of nodal coordinates and a list of bars

In [9]: node_xy = [[0,0], [1,2], [2,0], [3,2], [4,0]]
   ...: 
   ...: bars = [Bar(0,1), Bar(1,2), Bar(2,3), Bar(3,4),
   ...:         Bar(0,2), Bar(2,4),
   ...:         Bar(1,3)]

The drawing, abstracted in a function

In [10]: def graph(node_xy, bars):
    ...:     from matplotlib.ticker import MultipleLocator as ml
    ...:     from matplotlib.pyplot import annotate, subplots, show
    ...:     fig, ax = subplots(figsize=(8,8), constrained_layout=1)
    ...:     ax.scatter(*zip(*node_xy), zorder=8, color='r')
    ...:     for bar in bars:
    ...:         x0, y0, x1, y1 = node_xy[bar.i] node_xy[bar.j]
    ...:         ax.plot((x0,x1), (y0,y1), color='b', lw=2.5, zorder=6)
    ...:     for s in ax.spines.values() : s.set_visible(0)
    ...:     ax.xaxis.set_major_locator(ml(xmajor))
    ...:     ax.xaxis.set_minor_locator(ml(xminor))
    ...:     ax.yaxis.set_major_locator(ml(ymajor))
    ...:     ax.yaxis.set_minor_locator(ml(yminor))
    ...:     ax.tick_params(length=0, axis='both', which='both')
    ...:     ax.grid(1)
    ...:     ax.grid(1, 'minor', color='#ddeeff')
    ...:     ax.set_aspect(1)
    ...:     show()

And finally, we execute our function

In [11]: xmajor, xminor = 2, .5
    ...: ymajor, yminor = 2, .5
    ...: graph(node_xy, bars)

Does the above helps you?

Because I will not expand my answer, if you cannot proceed from this starting block then you should ask further, more focused questions.

CodePudding user response：

If you want a figure with x-y axes or a grid then Pyplot might be fine but if you're planning to make complicated stand-alone drawings like the one you show, you might want to consider generating an SVG drawing file from scratch. There are a few packages for making SVG files in Python such as