In my example the result should be 3 but it shows me 0. Count, if in
A:A = 1 AND B:B = (3 or 4 or 5).
I was trying something like that but it doesnt work:
=COUNTIFS(A:A; 1; B:B; OR(B=3;B=4;B=5))
------------------------ EDIT:
Let's say I have one more colum with characters:
And I want to count only the character with "a".
CodePudding user response:
Use formula like shown below, since commented above:
• Formula used in cell E2
=SUM(COUNTIFS(A:A,1,B:B,{3,4,5}))
Or,
• try using SUMPRODUCT()
SUMPRODUCT(COUNTIFS(A:A,1,B:B,{3,4,5}))
After OP has edited post:
Alternative versions & required output shown below:
• Formula used in cell F2
=SUM(COUNTIFS(A:A,1,B:B,{3,4,5},C:C,"a"))
• In German Version:
=SUMME(ZÄHLENWENNS(A:A;1;B:B;{3.4.5};C:C;"a"))
• Formula used in cell G2
=SUM((A2:A10=1)*(C2:C10="a")*(B2:B10={3,4,5}))
• In German Version:
=SUMME((A2:A10=1)*(C2:C10="a")*(B2:B10={3.4.5}))
• Formula used in cell H2
=SUM(MMULT(--((A2:A10=1)*(C2:C10="a")*(B2:B10={3,4,5})),{1;1;1}))
• In German Version:
=SUMME(MMULT(--((A2:A10=1)*(C2:C10="a")*(B2:B10={3.4.5}));{1;1;1}))
CodePudding user response:
You can use this formula: =SUM(COUNTIFS(A2:A10,1,B2:B10,{3,4,5}))
But I would recommend to "outsource" the criteria for 3,4,5 to an extra range. Then it is much easier to update the filter if necessary.