Find words inside dict-list-CodePudding

#I need to print if i found problem='FRAUDED BILL' or another phrase inside of those dict and print your respective key, (ex: EP1_2) for FRAUDED BILL

dict_ep = {'EP1_2':['FRAUDED BILL','IMPROPER BILLING - FRAUDED CARD (CARDS)','EMBEZZLEMENT','FRAUD'], 
            'EP1_4':['2nd COPY OF CONTRACT (CONSIGNEE)','ACCIDENT WITH DISPOSED VEHICLE'],
            'EP1_6':['BANK STRIKE'],
            'EP1_8':['ACCESS TO BALANCE AND CARD LIMIT','PAYMENT AGREEMENT']}

problem = ('frauded bill').upper()


for i in dict_ep:
    if problem == dict_ep.keys():
        print('EP found')
    else:
        print('EP no exist, try again!')

RESULTS:

EP no exist, try again!
EP no exist, try again!
EP no exist, try again!
EP no exist, try again!

CodePudding user response：

You can use any() to test if the string is found in list:

dict_ep = {
    "EP1_2": [
        "FRAUDED BILL",
        "IMPROPER BILLING - FRAUDED CARD (CARDS)",
        "EMBEZZLEMENT",
        "FRAUD",
    ],
    "EP1_4": [
        "2nd COPY OF CONTRACT (CONSIGNEE)",
        "ACCIDENT WITH DISPOSED VEHICLE",
    ],
    "EP1_6": ["BANK STRIKE"],
    "EP1_8": ["ACCESS TO BALANCE AND CARD LIMIT", "PAYMENT AGREEMENT"],
}

problem = "frauded bill".upper()

for key, lst in dict_ep.items():
    if any(problem in v for v in lst):
        print("EP Found:", key)
    else:
        print("EP NOT Found:", key)

Prints:

EP Found: EP1_2
EP NOT Found: EP1_4
EP NOT Found: EP1_6
EP NOT Found: EP1_8