I have (N,2) numpy array :
[3,5]
[4,2]
[1,6]
[5,4]
.....
I want to swap the values on every row so that the bigger value is FIRST
[5,3]
[4,2]
[6,1]
[5,4]
.....
CodePudding user response:
You could use something like this:
array.sort()
array = array[:, ::-1]
if array
is your numpy array
CodePudding user response:
ori_arr = np.array([[3, 5], [4, 2], [1, 6], [5, 4]])
print('''{}
The original array:
{}
'''.format("="*20, ori_arr))
# Straight forward way
for i in range(len(ori_arr)):
ori_arr[i] = sorted(ori_arr[i], reverse=True)
print('''{}
The swapped array:
{}
'''.format("="*20, ori_arr))
CodePudding user response:
Below is the answer i tried and i got the output , there could be efficient methods as well.
import numpy as np
x=np.array([[1,2],[3,4],[7,6]])
for i in x :
if i[0] >= i[1]:
else:
a= i[0]
i[0]= i[1]
i[1]= a
print(x)