How to get the ceil and floor of a date time in java-CodePudding

if I have a date as 2022-10-26T08:05:00.123Z, how can I get the ceil and floor of it.

So how can I get this below expected output in java?

floor: 2022-10-26T00:00:00.000Z

ceil: 2022-10-27T00:00:00.000Z

I want to basically add a comparison if the given date lies between floor and ceil so that it will return all the dates that lies within them.

CodePudding user response：

To get the floor you can use the atStartOfDay() method of LocalDate:

LocalDate.now().atStartOfDay().toString()

To get the ceiling you can add 1 day then use the atStartOfDay() method again.

LocalDate.now().plusDays(1).atStartOfDay().toString()

CodePudding user response：

Try this:

  LocalDate floor = LocalDate.now();
  LocalDate ceil = floor.plusDays(1);
  DateTimeFormatter formatter = DateTimeFormatter.ofPattern("uuuu-MM-dd'T'HH:mm:ss.SSS");
  System.out.println("floor: "   floor.atStartOfDay().format(formatter));
  System.out.println("ceil: "   ceil.atStartOfDay().format(formatter));

If your use case is just for checking that the date lies between ceil and floor, then formatting is not needed at all.