How to change a string name in a file when a hexadecimal numbers is split?-CodePudding

I have a file named input.txt.

name="XYZ_PP_0" number="0x12" bytesize="4" info="0x00000012"
name="GK_LMP_2_0" number="0xA5" bytesize="8" info="0x00000000bbae321f"
name="MP_LKO_1_0" number="0x356" bytesize="4" info="0x00000234"
name="PNP_VXU_1_2_0" number="0x48A" bytesize="8" info="0x00000000a18c3ba3"
name="AVU_W_2_3_1" number="0x867" bytesize="1" info="0x0b"

From this file i need to create another file output.txt. in this file if bytesize="8" then info is split in to two.

eg: number="0x48A" bytesize="8" info="0x00000000a18c3ba3"

then output file will contain:

name="PNP_VXU_1_2_0_LOW" number="0x48A" info="0xa18c3ba3"
name="PNP_VXU_1_2_0_HIGH" number="0x4BC" info="0x00000000"

where 0x4BC = 0x48A 0x32

this is current code:

import re                                                     

infile_path = "./input.txt"
outfile_path = "./output.txt"

with open(infile_path, "r") as infile, open(outfile_path, "w") as outfile:
    for s in infile:
        r = re.match('number="(.*)" bytesize="(.*)" info="(.*)"', s)
        if r:
            num, bs, info = map(lambda x: int(x, 0), r.groups())
            l = len(r.group(3)) - 2
            if bs == 8:
                l = 8
                nums = (num, num   0x32)
                infos = (info % (2**32), info // (2**32))
            else:
                nums = (num, )
                infos = (info, )
            for num, info in zip(nums, infos):
                outfile.write(f'number="{num:#x}" info="{info:#0{l 2}x}"\n')

output.txt for this code:

number="0x12" info="0x00000012"
number="0xA5" info="0xbbae321f"
number="0xD7" info="0x00000000"
number="0x356" info="0x00000234"
number="0x48A" info="0xa18c3ba3"
number="0x4BC" info="0x00000000"
number="0x867" info="0x0b"

Expected Output:

name="XYZ_PP_0" number="0x12" info="0x00000012"
name="GK_LMP_2_0_LOW" number="0xA5" info="0xbbae321f"
name="GK_LMP_2_0_HIGH"number="0xD7" info="0x00000000"
name="MP_LKO_1_0" number="0x356" info="0x00000234"
name="PNP_VXU_1_2_0_LOW" number="0x48A" info="0xa18c3ba3"
name="PNP_VXU_1_2_0_HIGH" number="0x4BC" info="0x00000000"
name="AVU_W_2_3_1" number="0x867" info="0x0b"

How can i add the LOW and HIGH to the name if byte size is 8?

CodePudding user response：

With your current code you just need to capture the name with the regex and add it to the output in the same way you handle nums:

with open(infile_path, "r") as infile, open(outfile_path, "w") as outfile:
    for s in infile:
        r = re.match('name="(.*)" number="(.*)" bytesize="(.*)" info="(.*)"', s)
        if r:
            name, *numbers = r.groups()
            num, bs, info = map(lambda x: int(x, 0), numbers)
            l = len(r.group(3)) - 2
            if bs == 8:
                l = 8
                names = (f'{name}_LOW', f'{name}_HIGH')
                nums = (num, num   0x32)
                infos = (info % (2**32), info // (2**32))
            else:
                names = (name, )
                nums = (num, )
                infos = (info, )
            for name, num, info in zip(names, nums, infos):
                outfile.write(f'name="{name}" number="{num:#x}" info="{info:#0{l 2}x}"\n')

CodePudding user response：

The regex is compiled at the beginning to improve performance.

The process() function analyzes an input line and writes to the output file.

PATTERN = re.compile(r'(\w*)="([^"]*)')

def process(line, f_out):
    name, number, bytesize, info = [x[1] for x in PATTERN.findall(line)]
    if int(bytesize) == 8:
        n = int(number, 16)   0x32
        f_out.writelines(
            [
                f'name="{name}_LOW" number="{number}" info="0x{info[-8:]}"\n',
                f'name="{name}_HIGH" number="0x{n:02X}" info="{info[:10]}"\n'
            ]
        )
    else:
        f_out.writelines(line)

with open("input.txt") as f_in, open("output.txt", "w") as f_out:
    for line in f_in:
        process(line, f_out)