Iterating over date range in python and setting the start and end date-CodePudding

I know this question is a repeated one. But what I am trying to do is, I want to iterate through a date range and for each iteration i need to set the fromDate and toDate.

for ex: If I give the date range as startDate = '2022-10-31' and endDate = '2022-11-04'

and for each iteration fromDate = '2022-10-31' and toDate = '2022-11-01' next iteration fromDate = '2022-11-01' and endDate = '2022-11-02' and so on.

I did some research and got to know how to iterate through dateRange. sample code:

import datetime
start_date = datetime.date(2022, 10, 31)
end_date   = datetime.date(2022, 11, 04)

dates_2011_2013 = [ start_date   datetime.timedelta(n) for n in range(int ((end_date - start_date).days))]

This just prints the incremented dates in the date Range. Am new to Python language. Any help is appreciated.

Thank you.

CodePudding user response：

You can change the code slightly to,

import datetime

start_date = datetime.date(2022, 10, 31)
end_date   = datetime.date(2022, 11, 4)

dates_2011_2013 = [ (start_date   datetime.timedelta(n), start_date   datetime.timedelta(n 1))  for n in range(int ((end_date - start_date).days))]


[(datetime.date(2022, 10, 31), datetime.date(2022, 11, 1)),
 (datetime.date(2022, 11, 1), datetime.date(2022, 11, 2)),
 (datetime.date(2022, 11, 2), datetime.date(2022, 11, 3)),
 (datetime.date(2022, 11, 3), datetime.date(2022, 11, 4))]

First item of the tuple is start date and the second item is end date.

CodePudding user response：

I want to iterate through a date range

another option is using while:

while start_date < end_date:
    print(start_date, start_date   datetime.timedelta(1))
    start_date  = datetime.timedelta(1)

'''
2022-10-31 2022-11-01
2022-11-01 2022-11-02
2022-11-02 2022-11-03
2022-11-03 2022-11-04