What I mean by this is if I have a table called payments with a created_at
column and user_id
column I want to select the count of purchases aggregated weekly (can be any interval I want) but only selecting first time purchases e.g. if a user purchased for the first time in week 1 it would be counted but if he purchased again in week 2 he would not be counted.
created_at | user_id |
---|---|
timestamp | 1 |
timestamp | 1 |
This is the query I came up with. The issue is if the user purchases multiple times they are all included. How can I improve this?
WITH dates AS
(
SELECT *
FROM generate_series(
'2022-07-22T15:30:06.687Z'::DATE,
'2022-11-21T17:04:59.457Z'::DATE,
'1 week'
) date
)
SELECT
dates.date::DATE AS date,
COALESCE(COUNT(DISTINCT(user_id)), 0) AS registrations
FROM
dates
LEFT JOIN
payment ON created_at::DATE BETWEEN dates.date AND dates.date::date '1 ${dateUnit}'::INTERVAL
GROUP BY
dates.date
ORDER BY
dates.date DESC;
CodePudding user response:
You want to count only first purchases. So get those first purchases in the first step and work with these.
WITH dates AS
(
SELECT *
FROM generate_series(
'2022-07-22T15:30:06.687Z'::DATE,
'2022-11-21T17:04:59.457Z'::DATE,
'1 week'
) date
)
, first_purchases AS
(
SELECT user_id, MIN(created_at:DATE) AS purchase_date
FROM payment
GROUP BY user_id
)
SELECT
d.date,
COALESCE(COUNT(p.purchase_date), 0) AS registrations
FROM
dates d
LEFT JOIN
first_purchases p ON p.purchase_date >= d.date
AND p.purchase_date < d.date '1 ${dateUnit}'::INTERVAL
GROUP BY
d.date
ORDER BY
d.date DESC;