Selenium, Python, Chrome Driver -Send

could someone kindly point out to me where I'm going wrong please?

I've looked up the documentation and I thought I set it up correctly but keep getting the error:

line 29, in <module>
    username.send_keys(cred_username)
    ^^^^^^^^^^^^^^^^^^
AttributeError: 'list' object has no attribute 'send_keys'

Currently I can:

Load and access the page
get past the security wall my browser throws up
load up the log in screen, but am not able to input my credentials.


from selenium import webdriver
from selenium.webdriver.chrome.service import Service
from selenium.webdriver.common.keys import Keys
import time
from selenium.webdriver.common.by import By
from selenium.webdriver.support.wait import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC

cred_username = "username"
cred_password = "password"

s_1=Service("my driver location")
driver = webdriver.Chrome(service=s_1)

driver.get("https:website")

# Hurdle 01 Start : get past security step.
advanced = driver.find_element(By.ID, "details-button")
advanced.click()

proceed = driver.find_element(By.ID, "proceed-link")
proceed.click()
# Hurdle 01 Finish : 

# Hurdle 02 Start : logging in
username = driver.find_elements(By.ID, "idUsername")
username.clear()
username.send_keys(cred_username)
password = driver.find_element(By.ID, "idPassword")
password.clear()
password.send_keys(cred_password)
password.send_keys(Keys.RETURN)

time.sleep(99)

I've tried setting it as a string but get the same error. I've also tried a variation of "send_keys_to_element(element, *keys_to_send)" I've also tried setting an xPATH but get the same results.

If anyone can point out where I'm going wrong or direct to a web page that explains where I'm going wrong I'd really appreciate it, thanks for having a look.

I thought what I had written would allow me to simply input my log-in details at this stage so I can then access a page which would allow me to upload a document. This is the only part of the process that requires input from a keyboard.

Update from answer:

Thanks for the answer [Prophet], I've removed the 's' as you suggest and tried using the XPATH again, but now have this error come up, I feel I'm close but there's something obvious I'm missing.

  File "/Users/jace/Desktop/Filing_Cabinet/Python_Folder/my_phone_config01.py", line 27
    username = driver.find_element(By.XPATH, "//input[@id="Username"]")
                                             ^^^^^^^^^^^^^^^^^^^^^^
SyntaxError: invalid syntax. Perhaps you forgot a comma?
[Finished in 25ms with exit code 1]

Update from comment: pitcture of the inspection page

Resolved, Final update

Prophet had pointed out I may of needed to wait for the page to load fully, hence why I was having a hard time finding the element to send keys to.

Adding a wait allowed the element to actually load for my script to locate it.

# Step 03 Start : logging in
try: 
    username = WebDriverWait(driver, 5).until(
        EC.presence_of_element_located((By.XPATH, "//input[@id='idUsername']"))
    )
    username.send_keys(cred_username)
 
    password = WebDriverWait(driver, 5).until(
        EC.presence_of_element_located((By.XPATH, "//input[@id='idPassword']"))
    )
    password.send_keys(cred_password)
    password.send_keys(Keys.RETURN)
# Step 03 End : need to add wait commands/let the page load.
finally:
    time.sleep(30)

CodePudding user response：

Your mistake is here: username = driver.find_elements(By.ID, "idUsername")
You need to use find_element method, not find_elements since find_element returns a web element object so you can apply send_keys method on it, while find_elements returns a list of web element and you can not apply send_keys method on a list.
UPD
As about your additional issue.
The following XPath expression can be fixed as following:

username = driver.find_element(By.XPATH, "//input[@id='Username']")

username = driver.find_element(By.XPATH, '//input[@id="Username"]')

The rule is simple: in case you enclose the string with ", the internal strings should be enclosed with ' and wise versa.