I wanted to ask. if there is an efficient way to split a string and ignore inner strings of is

Example: I get a string in this format:

s = 'name,12345,Hello,\"12,34,56\",World'

and the output I want, is:

['name', '12345', 'Hello', "12,34,56", 'World']

by splitting at the "," the numbers become separated:

['name', '12345', 'Hello', '"12', '34', '56"', 'World']

I know I could split at \" and split the first and the third part separately, but this seems kind of inefficient to me

CodePudding user response：

This job belongs to the csv module:

import csv

out = next(csv.reader([s], skipinitialspace=True))
# out is
# ['name', '12345', 'Hello', '12,34,56', 'World']

Notes

• The csv library deals with comma-separated values, perfect for this job
• It understands quotes, which your input calls for
• The csv.reader takes in a sequence of texts (i.e. lines of text)
• The skipinitialspace flag is just that: it tells the reader to skip initial spaces before each value

CodePudding user response：

If your string separates each element with a comma and a space you could pass ", " to your split method like this:

>>> s = 'name, 12345, Hello, \"12,34,56\", World'
>>> print(s.split(", "))
['name', '12345', 'Hello', '"12,34,56"', 'World']

CodePudding user response：

You can try built-in csv module to parse the string:

import csv
from io import StringIO

s = 'name, 12345, Hello, "12,34,56", World'

print(next(csv.reader(StringIO(s), skipinitialspace=True)))

Prints:

['name', '12345', 'Hello', '12,34,56', 'World']