Elif syntax error with nested if conditions-CodePudding

The interpreter gives me a syntax error when it reaches elif in the code below. Why?

while walls:
    rand_wall = walls[int(random.random()*len(walls))-1]
    if rand_wall[1] != 0 and rand_wall[1] != mazeheight-1:
        if maze[rand_wall[0][rand_wall[1]-1] == "u" and maze[rand_wall[0][rand_wall[1] 1] == "c":
            print("no")
        elif maze[rand_wall[0][rand_wall[1]-1] == "c" and maze[rand_wall[0][rand_wall[1] 1] == "u":
            print("no")

If the first condition is true, I want to check a second condition and its mirror condition and run some code (replaced with print("no") for debugging) if either condition is true.

CodePudding user response：

There are some closing brackets missing.

while walls:
    rand_wall = walls[int(random.random()*len(walls))-1]
    if rand_wall[1] != 0 and rand_wall[1] != mazeheight-1:
        if maze[rand_wall[0][rand_wall[1]-1] == "u" and maze[rand_wall[0][rand_wall[1] 1]]] == "c": # added two closing brackets before the == sign.
            print("no")
        elif maze[rand_wall[0][rand_wall[1]-1] == "c" and maze[rand_wall[0][rand_wall[1] 1]]] == "u": # same as before
            print("no")

It should run now, but I don't know the expected behavior. Next time try to post the full stack trace.

CodePudding user response：

I would clean this up to avoid the chance of syntax error. I'm assuming, for example, that

maze[rand_wall[0][rand_wall[1]-1]

should be

maze[rand_wall[0]][rand_wall[1]-1] 
                 ^
                 add missing ]

while walls:
    x, y = random.choice(walls)
    if y != 0 and y != mazeheight-1:
        row = maze[x]
        if row[y-1] == "u" and row[y 1] == "c":
            print("no")
        elif row[y-1] == "c" and row[y 1] == "u":
            print("no")