Wrote a script, the main task of which is to upload and download files.

#!/bin/bash

fileUpload() {
  local filepath=$1
  local transfer_path=$2
  local url

  url=$(curl --progress-bar --upload-file "$filepath" "https://transfer.sh/$transfer_path")

  echo "$url"
}

printOutUpload() {
  local filepath=$1
  local url

  echo "Uploading $filepath"

  url=$(fileUpload "$filepath")

  echo "Transfer File URL: $url"
}

fileDownload() {
  local destination=$1
  local url=$2
  local file_name=$3

  curl -# "https://transfer.sh/$url/$file_name" -o "$destination/$file_name"
}

printOutDownload() {
  if [ $? -eq 0 ]; then
    echo "Success!"
  else
    echo "Error: There was a problem downloading the file."
  fi
}

while getopts "d:" opt; do
  case $opt in
    d)
      printOutDownload
      fileDownload "$2" "$3" "$4"
      ;;
    \?)
      echo "Invalid option: -$OPTARG" >&2
      exit 1
      ;;
  esac
done

With flag -d script download single file from the transfer:

./script -d ./tests HJkv1I test.txt

Without it should upload files:

./script test.txt test1.txt

One by one, each of these functions work correctly, but I can't get them to work in one script - If I add the -d flag, downloading is working, but upload not, its do nothing

CodePudding user response：

Set a flag when processing the arguments. Then after the getopts loop, use an if statement to perform an upload or download depending on the flag.

direction=up

while getopts "d:" opt; do
  case $opt in
    d) direction=down
      ;;
    \?)
      echo "Invalid option: -$OPTARG" >&2
      exit 1
      ;;
  esac
done

shift (($OPTIND-1))

if [[ $direction == up ]]
then
    printOutUpload
    fileUpload "$@"
else
    printOutDownload
    fileDownload "$@"
fi