Converting a string to list through python-CodePudding

The string value

value = "[new=user,pass=h[]@,repalce=que]"

I need the output to be as a list

list = [ "new=user","pass=h[]@","repalce=que" ]

  

I am new to python just want to know how to deal with these type convertions

CodePudding user response：

You can use the split method as follows:

value = "[new=user,pass=h[]@,repalce=que]"

splitList = value.split(",")

print(splitList)

The split method takes the character that you want to split the sentence on as a parameter.

CodePudding user response：

You can do that in this particular case by the following command

value_list = value[1:-1].split(',')

This way you will first get rid of the brackets (first and last character) and then split by the comma. I do not think there is a more elegant way since this is a rather rare case. I would recommend loading lists as lists or other variables in their correct format and avoid changing the type.

CodePudding user response：

you can use str.split

value = "[new=user,pass=h[]@,repalce=que]"
result = value.split(',')

please note that list is a type. I recommend not to use it as a variable name.

CodePudding user response：

You could do it using a list comprehension like this:

value = "[new=user,pass=h[]@,repalce=que]"

new_value = [t.replace('pass', 'test') for t in value[1:-1].split(',')]

print(new_value)

Output:

['new=user', 'test=h[]@', 'repalce=que']

Note:

This only works for this particular case.

Also, there's no "type conversion" here

CodePudding user response：

Clean the string thyen convert string to list by string.split()

value = "[new=user,pass=h[]@,repalce=que]"
value = value [1:-1].split(",")
print(value)

output #

['new=user', 'pass=h[]@', 'repalce=que']

CodePudding user response：

i assume the []@ is not supposed to be taken as list . so this is my solution ,maybe it would be better to sue regex but whatever

value = "[new=user,pass=h[]@,repalce=que]"
def func(x):
    n=len(x)
    x=list(x)
    s=e=-1
    for i in range(0,n-2,1):
        if x[i]=='[' and x[i 1]!=']' and x[i 2]!='@':s=i
        if x[i]==']' and x[i-1]!='[' and x[i 1]!='@':e=i
    x[s]=x[e]=''
    x=''.join(x)
    x=x.split(',')
    return x
print(func(value))

CodePudding user response：

To convert the string to a list, you can use the split() method. This method splits a string into a list of substrings based on a specified delimiter.

For example, you can use the following code to split the string on the , character:

value = "[new=user,pass=h[]@,repalce=que]"

list = value.split(',')
print(list)

This will output will be:

['[new=user', 'pass=h[]@', 'repalce=que]']

If you want to remove the square brackets from the beginning and end of the string, you can use the strip() method to remove them.

value = "[new=user,pass=h[]@,repalce=que]"

list = value.strip('[]').split(',')
print(list)

This will output will be:

['new=user', 'pass=h[]@', 'repalce=que']