In this example I want python to print the last number again if I say yes the code:

for i in range(1,11):
    print(i)
    a=input("back?")
    #if a=="yes":
        #want to do the last number again
    if a=="no":
        None

for example I want to print 2 again here

not from the beginning just the last one

CodePudding user response：

Use while loop instead of for and increase i only on the 'no' answers

i = 1
while i < 11:
    print(i)
    a = input("back?")
    if a == "yes":
        continue
    else:
        i  = 1

Output

1
back?no
2
back?no
3
back?yes
3
back?yes
3
back?no
4
back?yes
4

CodePudding user response：

I think this is what you want:

for i in range(1,11):
    print(i)
    a=input("back?")
    if a=="yes":
        #want to do the last number again
        print(i)

Example output:

1

back?no
2

back?yes
2
3

back?no
4

back?yes
4
5

back?

CodePudding user response：

• You don't need the else with None and keep in mind that no-op in Python is pass (and not None).
• Just print in the if and you are good to go imho.

for i in range(1,11):
    print(i)
    a=input("back?")
    if a=="yes":
        print(i)

CodePudding user response：

The key is to avoid advancing to the next iteration of the for loop until the user answers 'no' to the question. For that you can use a while loop to keep printing the same number until the break condition is met:

for i in range(1, 11):
    while True:
        print(i)
        if input('back?') == 'no':
            break

Demo: https://replit.com/@blhsing/CoordinatedSpecializedFolders