I need to insert values into multiple table. Please correct my code because it just double the inserted value on table_attendace
if(isset($_POST['text']))
{
$text =$_POST['text'];
// insert query
$sql = "INSERT INTO table_attendance(NAME,TIMEIN) VALUES('$text',NOW())";
$query =mysqli_query($conn,$sql) or die(mysqli_error($conn));
if($query==1)
{
$ins="INSERT INTO table_attendancebackup(NAME,TIMEIN) VALUES('$text',NOW())";
$quey=mysqli_query($conn,$sql) or die(mysqli_error($conn));
if ($quey==1) {
$_SESSION['success'] = 'Action Done';
}else{
$_SESSION['error'] = $conn->error;
}
}
}
CodePudding user response:
In the second query, you reused the first query $sql
again, instead of using $ins
.
It should be
$quey=mysqli_query($conn,$ins) or die(mysqli_error($conn));
CodePudding user response:
you can write two queries in single variable with semicolon then you can save the same data in both table.
And $quey=mysqli_query($conn,$sql) or die(mysqli_error($conn));-> in this line you placed the $sql variable wrongly instead of $ins.
$sql = "INSERT INTO table_attendance(NAME,TIMEIN) VALUES('$text',NOW()); INSERT INTO table_ttendancebackup(NAME,TIMEIN) VALUES('$text',NOW())";
$query=mysqli_query($conn,$sql) or die(mysqli_error($conn));