Is there a C# function or overload to Math.Round that will allow abnormal rounding practices?-CodePudding

I have the need to round a number for pricing sort of strangely as follows:

the value of an incoming price will be 3 decimal places (ie. 10.333)

It is necessary to round the first decimal place up if any number past said first decimal place is greater than 0.

for example:

10.300 = 10.3,
10.301 = 10.4,
10.333 = 10.4

before I go creating a custom method to do this I was wondering if anyone was aware of an existing usage/overload of Math.Round() or other already existing package to get this desired result?

CodePudding user response：

Math.Round has an overload that accepts a MidpointRounding enum value, which lets you specify the strategy for rounding.

In your case, you always want to round up, which is called ToPositiveInfinity.

Math.Round(yourValue, 1, System.MidpointRounding.ToPositiveInfinity)

CodePudding user response：

Approach with Math.Ceiling()

decimal input = 10.300m;
decimal result = Math.Ceiling(input * 10m) / 10m;

https://dotnetfiddle.net/Vck4Oa

CodePudding user response：

double d = 10.300;
var result= Math.Ceiling((decimal)d * 10) / 10;