How to print an attribute of an object from within a list-CodePudding

If I have a list in Python that contains objects with class attributes, how can I print the list of objects but only a specific attribute?

For example:

I have an object with the attribute of NAME with NAME being = to Cat. I have another object with the NAME attribute being = to Dog.

Both objects are in a list and I want to print all the objects.NAME only

Here is some example code (very poorly & quickly written)

class play_object():
    def __init__(self, weight, size, name):
        self.weight = weight
        self.size = size
        self.name = name

objects = []

car = play_object(6, 10, "Car")
cat = play_object(0.5, 1, "Cat")

objects.append(car)
objects.append(cat)

print(objects)

This outputs:

[<__main__.play_object object at 0x000001D0714053D0>, <__main__.play_object object at 0x000001D0712ACF90>]

Amending the code to have:

print(objects.name)

Results in the output:

Traceback (most recent call last):
  File "C:/Users//AppData/Local/Programs/Python/Python311/Test2.py", line 15, in <module>
    print(objects.name)
AttributeError: 'list' object has no attribute 'name'

So what is the correct way to just print the selected attribute from objects in the list?

CodePudding user response：

As you created car and cat as an object of class play_object use object name with attribute to get the data

print(car.name)
print(cat.name)

Instead of using:

print(object.name)

As object is list

CodePudding user response：

Firstly you need to iterate elements in list. then you need to print each attributes of objects.

for object in objects:
    print(i.name)

Your wrong: Your are trying to get name of list. But your objects have name attribute instead of list. So you need to print name of objects