Here is how I defined and assigned a string array at the same time

#include <stdio.h>
#include <cs50.h>
#include <string.h>

int main()
{
    string word = get_string("Enter a Word;");

    for(int i = 0; i<strlen(word); i  )
    {
        printf("%c\n",word[i]);
    }
}

Now I want to apply the same technique for taking integer values from user

#include <stdio.h>
#include <cs50.h>

int main()
{
    int scores[] = get_int("Enter score:");
    int len = sizeof(scores)/sizeof(int);

    for(int i = 0; i<len; i  )
    {
        printf("%i\n", scores[i]);
    }
}

But the code doesn't get compiled and compiler says like this:

IntArray.c:5:9: error: array initializer must be an initializer list or wide string literal
    int scores[] = get_int("Enter integer:");
        ^
1 error generated.
make: *** [<builtin>: IntArray] Error 1

I know we have a for loop for that solution, which goes like this: That's why I have to keep using for loop, which looks like this:

#include <stdio.h>
#include <cs50.h>

int main()
{
    int scores[3];

    for(int I = 0; I<3; I  )
    {
        score[I] = get_int("Enter score:);
    }

    for(int j =0; j<3; j  )
    {
        printf("%I\n", scores[j]);
    }
}

My question is can I define and assign the integer array at the same time?

I tried to define and assign an integer array at the same time as we do with the single string, but I couldn't.

CodePudding user response：

Building on this earlier answer. The function read_ints reads integers until it reads end_of_list, after which it returns.

void read_ints(Array *a, int end_of_list)
{
    int current;
    while(1){
        scanf("%d",&current);
        if(current == end_of_list) return;
        insertArray(a,current);
    }
}
int main()
{
    Array a;
    initArray(&a, 5);
    printf("Enter numbers:");
    read_ints(&a,-1);

    for(int i=0; i<a.used; i  ) printf("%d ", a.array[i]);
    return 0;
}

CodePudding user response：

Can I define and assign an integer array at the same time like we do with the string array?

string word is not an array. That object is of a CS50 type string, which is a pointer, that points to an array of char.
Arrays are not pointers.
Pointers are not arrays.

Code can create similar code to define an int pointer ...

// string word = get_string("Enter a Word;");
int *ints = get_ints("Enter ints;");

... and use a special value, like INT_MIN, to denote the end of the array of ints. Of course then INT_MIN is not available as a value to read. This is analogous to C strings, which uses a special value, the null character to signify the end of the array.

My question is can I define and assign the integer array at the same time?

Yes.

See @M.M comment.

int scores[] = { get_int("Enter score:"), get_int("Enter score:"), get_int("Enter score:") };

This obliges that the array size is determined before getting the data.

Code could read the ints into some collection of data, then use the int count to define a variable length array (VLA). But VLAs may not be initialized. They could be assigned later.

some_tbd_data_collection_type data = 0;
unsigned n = get_ints(&data);
int a[n];
for (unsigned i = 0; i < n; i  ) {
  a[i] = get_int(&data, i);
}
data_free(&data);