I have a list in which the rows from the data frame are stored.
kl <- list(structure(list(GROUP = "1", col6 = NA_character_, col7 = NA_character_,
dif = NA_character_, p.value = NA_character_), row.names = 1L, class = "data.frame"),
structure(list(GROUP = "2", col6 = NA_character_, col7 = NA_character_,
dif = NA_character_, p.value = NA_character_), row.names = 3L, class = "data.frame"),
structure(list(GROUP = "3", col6 = NA_character_, col7 = NA_character_,
dif = NA_character_, p.value = NA_character_), row.names = 5L, class = "data.frame"),
structure(list(GROUP = "4", col6 = NA_character_, col7 = NA_character_,
dif = NA_character_, p.value = NA_character_), row.names = 7L, class = "data.frame"))
how to get the line number from the list and write it to a vector
kl.vec <- c(1,3,5,7)
CodePudding user response:
Test data as below:
kl <- list(structure(list(GROUP = "1", row.names = 1, class = "data.frame")),
structure(list(GROUP = "2", row.names = 3, class = "data.frame")),
structure(list(GROUP = "3", row.names = 5, class = "data.frame")),
structure(list(GROUP = "4", row.names = 7, class = "data.frame")))
then we can do
sapply(c(1:length(kl)), FUN=function(x) kl[[x]]$row.names)
it returns
1 3 5 7